[ROVERNET - UK] P6 2000 TC servo boost

[David Sheuring]

YIKES!!!!!! and I lost him on the first line.

All I want to know is where you can get a booster kit
for the 2000TC boosters including the little round
rubber bit that is hard to find?

I would welcome anyone with an answer
Cheers
David Sheuring
--- JULIET KEILER <lingfield51 at btinternet.com> wrote:

> Ah yes but will it damage the head of my nodding dog
> on the back parcel shelf if I lock all four wheels ?
> :)
> 
> Admire the maths Paul and far to dim to challenge
> it!  :)
> 
> Alan Francis (partviking)
> 
> ----- Original Message ----
> From: Netspace <vmitps at netspace.net.au>
> To: rovernet at lyris.ccdata.com
> Sent: Monday, 3 December, 2007 8:40:53 AM
> Subject: Re: [ROVERNET - UK] P6 2000 TC servo boost
> 
> The air chamber size affects the maximum force it
> can exert.
> To wit:
> Assume diameter of 7"
> area = (7 * .0254metres)sqaured*pi/4  =  .0248
> square metres
> Pressure difference maximum is 100kPa, so the force
> is
> F = area * pressure = .0248 *100 * 1000 N = 2480N
> The piston is, what, .875"? don't have one to
> measure right now
> this gives an area of .000388 sq metres, so the
> pressure in the fluid is 
> 6.392MPa
> The slave piston area is (guessing size here since I
> haven't looked at a P6B 
> front caliper):
> front piston area + rear piston area
> (60mm squared * pi / 4 * 4) + (12mm squared *pi /4 *
> 4)
> = (.011sq m) + (.00045sq m)
> = .0115 square metres
> This times the fluid pressure gives the force on to
> the discs of 73KN 
> (average, I should work out the split front to
> rear...)
> Usual coefficient of friction between pad and disc
> is 0.4
> Now the braking force on the rotor actually involves
> integrating the force 
> elements across the pad, for different rotor radii. 
> I can't be bothered 
> doing that right now, so I shall use rull of thumb
> that 2/3 of the pad 
> distance (going radially) is the radius of action. 
> This gives about 250mm 
> diameter.
> Now the tyre longitudinal force is the inverse of
> the disc effective 
> diameter and the tyre diameter (to contact patch, a
> bit less than the free 
> diameter) times the disc torque braking force.
> Tyre diam is roughly .63m, so ratio is .25/.63 = 0.4
> This gives at tyre force of :
> disc side force * coeff * torque ratio
> =  73KN * 0.4 * 0.4
> =  11.7KN at tyre perimeter
> Weight force on tyre = 300kg * g  (good old F = MA,
> and assuming that all 
> wheels carry equal down force which is rubbish when
> braking) (totally making 
> assumptions here, worse than an evolutionist)
> =  2940N (or 2.94KN)
> Rubber to road coefficient of friction is around 1.0
> on a road tyre (higher 
> on track tyres),
> so there is Plenty of force to lock the wheel.
> If the front wheels took the full weight of the car,
> they'd handle around 
> 5KN braking force.  Their ability proportionally
> drops as the force 
> increases.
> 
> Paul Smith (eh!)
> 
> ----- Original Message ----- 
> From: "Vern Klukas" <vern at inkspotco.com>
> To: <rovernet at lyris.ccdata.com>
> Sent: Monday, December 03, 2007 3:57 AM
> Subject: RE: [ROVERNET - UK] P6 2000 TC servo boost
> 
> 
> >I did a little research on this, it appears thw
> size of the vacuum piston 
> >is irrelevant, it is the ratio between the area of
> the control piston (the 
> >little one that operates the airvalve) and the
> slave cylinder (the main 
> >hydraulic bore of the servo) that counts.
> >
> > Based on that, the ratio should be 2.78:1, which
> is the same number as the 
> > Girling MkII servo used on the P4 110  ( 
> > www.head2head.free-online.co.uk/Rover/servo.htm )
> >
> > Perhaps more later, I'm going to poke around a bit
> more.
> >
> > Yours
> > Vern
> > -- 
> > Vern Klukas                            I'm a
> little . . .
> > Inkspot Type & Design
> > vern at inkspotco.com
> >
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> > 
> 
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