[ROVERNET - UK] Battery in Boot?

roger matheson rogerdm at iprimus.com.au
Sat Sep 11 14:24:04 BST 2004


Clearly the solution to the voltage drop of having the battery in the boot
is to move the engine there as well

Roger
----- Original Message -----
From: "Richard Elliott" <relliott44 at yahoo.com>
To: <rovernet at lyris.ccdata.com>
Sent: Saturday, September 11, 2004 12:25 AM
Subject: Re: [ROVERNET - UK] Battery in Boot?


> Hi Eric,
>
> One thing about electronics and electrical- there's
> probably a formula and a code.
>
> For the battery relocation issue, there will
> definitely be a voltage drop for a given wire
> diameter, and there is also the allowable drop
> percentage to consider, which is addressed in U.S. in
> the NEC as 2%.  Any figure for voltage drop has to be
> considerate of current 'I' (constant current), length
> 'L' and voltage 'V'.  Putting everything together, a
> figure for 'Circular mils' CM (wire diameter) is
>
> CM = (25 x I x L) / V
>
> Richard Elliott
> 1970 NADA P6B Tobacco Leaf
>
> --- Eric Russell <p6rovers at yahoo.com> wrote:
>
> > Tom,
> > My first career involved installing RADAR and depth
> > sounders on both deep sea ships, tug boats, and
> > fishing boats.  The small craft were fitted with a
> > small AC generator run by the boats' DC batteries.
> > It
> > was always our objective to get the generator as
> > close
> > as we could to the batteries to avoid voltage loss.
> > I
> > have now forgotten the mathematic formula to
> > calculate
> > the voltage drop for a length of wire based upon its
> > diameter.  Perhaps somebody can help with that.
> >
> > I think it creates another variable for you with
> > regard to starting power but I thought I should give
> > you a caution rather than just reading and moving
> > on.
> >
> > Eric
> >
> >
> > =====
> > Webmaster & Magazine Editor:
> > The Rover Car Club of Canada -  www.roverclub.ca
> >
> >
> >
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>
>
>
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